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Continuity
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0:47
Q) Simplify : sin(coπ ππ^(β1) 17/8)}#class12maths #shivangmathsacademy #cbsemaths #cbsemaths
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2 weeks ago
YouTube
Shivang Maths Academy
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Multimeter Continuity Test β‘ #electronic #electric #diy
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Q) Express πππ§^(βπ) (ππ¨π¬π±/(πβπ¬π’π§π±)), (βππ)/π=π±=π/π in the simplest form.#class12
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2 weeks ago
YouTube
Shivang Maths Academy
1:50
Q) If π ππ πππ‘^(β1) (π₯+1)]=πππ (tan^(β1) π₯), π‘βππ ππππ π₯.#class12maths #shivang
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2 weeks ago
YouTube
Shivang Maths Academy
1:05
Draw the graph of π(π₯)=π ππ^(β1) π₯, π₯β[β1/β2, 1/β2]. Also, write range of f(x). #trigonometry
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3 weeks ago
YouTube
Shivang Maths Academy
2:11
Q) Check whether function f(x) defined as f(π₯)={((|π₯β3|)/(2(π₯β3)), π₯=3 (π₯β6)/6,π₯β₯3) Is
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2 weeks ago
YouTube
Shivang Maths Academy
1:52
Q) The value of tan[1/2 cos^(β1) (β5/3)] is (a) (3+β5)/2 (b) (3ββ5)/2(c) (β3+βg5)/2(d) (β3ββ5)/2
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3 weeks ago
YouTube
Shivang Maths Academy
1:07
Q) If π(π₯)={(sinπ₯/π₯+cosπ₯, π₯β 0 π, π₯=0) is continuous at π₯=0, then the value of π is :
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1 week ago
YouTube
Shivang Maths Academy
0:51
Q) Simplify : tan^(β1) {β((1βcosπ₯)/(1+cosπ₯))}}#class12maths #shivangmathsacademy #cbsemaths
2.4K views
2 weeks ago
YouTube
Shivang Maths Academy
1:58
Q) Simplify : tan^(β1) ((cos2π₯βsin2π₯)/(cos2π₯+sin2π₯)),0=π₯=π/4..#class12maths #shivangmathsaca
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3 weeks ago
YouTube
Shivang Maths Academy
1:50
Q) The function π defined by π(π₯)={ (π₯,f π₯β€1 5, if π₯= 1 is not continuous at(A) x=0(B) π₯
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Shivang Maths Academy
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JEE Advanced 2026 π₯ Same Concept Repeat! | Sachin Mor Sir #jeeadvanced #iitjee
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Find k so that π(π₯)={((π₯^2β2π₯β3)/(π₯+1), π₯β β1 π, π₯=β1) is continuous at x=β1.#cbse2027 #maths
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Shivang Maths Academy
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Q) If π(π₯)={ ((π₯^2β4π₯β5)/(π₯+1), π₯β β1 π,&π₯=β1 is continuous at π₯=β1, then the value of π i
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2 weeks ago
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Shivang Maths Academy
2:05
Q) Simplify: ππ¨π¬^(βπ) π±+ππ¨π¬^(βπ) [π±/π+β(πβππ±^π )/π]; π/πβ€π±β€π #cbsemaths #maths
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Q) The graph of a trigonometric function is as shown. Which of the following will represent graph of
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4 weeks ago
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Shivang Maths Academy
1:53
Q) If π(π₯)={((1βsin^3 π₯)/(3cos^2 π₯), for π₯β π/2 π, for π₯=π/2) is continuous at π₯=π/2, t
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1 week ago
YouTube
Shivang Maths Academy
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Q) Evaluate sin[cos^(β1) cos(7π/6)] #shivangmathsacademy #cbsemaths #class12maths #maths
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3 weeks ago
YouTube
Shivang Maths Academy
1:29
Q) Domain of π ππ^(β1) (2π₯^2β3) is (A) (β1,0)βͺ(1,β2)(B) (ββ2,β1)βͺ(0,1)(C) [ββ2,β1]βͺ[1,β2](D) (β
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